3(x+2)^2+7=3x^2+12x+33

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Solution for 3(x+2)^2+7=3x^2+12x+33 equation: 



3(x+2)^2+7=3x^2+12x+33

We move all terms to the left:

3(x+2)^2+7-(3x^2+12x+33)=0

We get rid of parentheses

-3x^2+3(x+2)^2-12x-33+7=0

We add all the numbers together, and all the variables

-3x^2-12x+3(x+2)^2-26=0

We move all terms containing x to the left, all other terms to the right

-3x^2-12x+3(x+2)^2=26

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